Enter the values for the variables that give the correct simplified expressions, x=>=0; sqrt(50x ^ 2) = sqrt(25 - 2x ^ 2) = 5x * sqrt(b); b =; sqrt(32x) = sqrt(16.2x) = e * sqrt(2x); c =; sqrt(38n) = sqrt(8 * 2 * pi) = e * sqrt(2n); e =; sqrt(72x ^ 2) = sqrt(36 * 2 * x ^ 2) = gx * sqrt(2); g =

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.

b

step-by-step explanation:

this is because the profit is decreasing and turning into debt