A and B are squares. The length of one side of square A is 4. The length of one side of square B is twice the length of a side of square A. What is the average (mean) area of the 2 squares?

40

Step-by-step explanation:

So square A has a side of 4, therefore its area is 16 because you square the side length.

Square B has a side of 2 times Square A's side. So Square B has sidelength 8 as 4*2 = 8.

If Square B has side length 8, it has an area of 64.

The average is found by adding the two area and then dividing by 2. So,

64 + 16 = 80

80/2 = 40

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step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

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