Help with question b please​

9514 1404 393

  (a) 5.82 cm (correctly shown)

  (b) 10.53 cm

Step-by-step explanation:

a) The length BC can be found from the law of sines:

  BD/sin(C) = BC/sin(D)

  BC = BC·sin(C)/sin(D) = (6 cm)sin(48°)/sin(50°) ≈ 5.82 cm

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b) The angle ABD is the sum of the angles shown:

  angle ABD = 50° +48° = 98°

We know the lengths BA and BD and the included angle ABD, so we can use the law of cosines to find AD.

  AD² = BA² +BD² -2·BA·BD·cos(98°)

  AD² ≈ 8² +5.82² -2(8)(5.82)(-0.139173) ≈ 110.8411

  AD ≈ √110.8411 ≈ 10.53 . . . . cm

could you reply to this with the question so i can ?

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6