Indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).

9514 1404 393

  x +3y = -3

Step-by-step explanation:

The midpoint of the segment with the given end points is ...

  M = ((4, 1) +(2, -5))/2 = (6, -4)/2 = (3, -2)

The difference between coordinates of the given points is ...

  (∆x, ∆y) = (4, 1) -(2, -5) = (2, 6)

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The equation of the perpendicular bisector can be written as ...

  ∆x(x -h) +∆y(y -k) = 0 . . . . line through (h, k) ⊥ to one with slope ∆y/∆x

  2(x -3) +6(y -(-2)) = 0

  2x +6y +6 = 0 . . . . . simplify to a general-form equation

To put this in standard form, we need the constant on the right, and all numbers mutually prime. We can subtract 6 and divide by 2 to get there.

  2x +6y = -6

  x + 3y = -3

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.