The angle of elevation to the top of the school is 37° from where you are standing
11.2 m from the wall of the school. Find
the height of the school.

8.44 m

Step-by-step explanation:

SohCahToa is a good way to remember that Sin = opposite/hypotenuse, Cosine = adjacent/hypotenuse and Tangent = opposite/adjacent. In this case, we have to use tangent. So tan 37° = x/11.2. Multiply both sides by 11.2 and you get tan 37° × 11.2 = x; The height of the school is x so the height of the school is 8.44 m

i think 5 miles per hour

step-by-step explanation: