Two ships leave a harbor at the same time. One ship travels on a bearing S15degreesW at 11 miles per hour. The other ship travels on a bearing N75degreesE at 12 miles per hour. How far apart will the ships be after 2 ​hours?

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

the answer would be c:   ax + b = ax + c

step-by-step explanation:

sorry i just need to anwers this to get points

step-by-step explanation:

you can not solvr this without numbers