If a line has a slope of -2 and goes through the point (1, -3), then the equation for the line in slope-intercept form is what?

y = -2x - 1

Step-by-step explanation:

Plug in the slope and given point into slope intercept form, y = mx + b, and solve for b:

y = mx + b

-3 = -2(1) + b

-3 = -2 + b

-1 = b

Plug in the slope and y intercept into y = mx + b:

y = mx + b

y = -2x - 1

So, the equation of the line is y = -2x - 1

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.