If x=4(3-y)(2^2-1), what is the value of y in terms of x?

hello there...

x = 4(3-y)(4-1)

x =( 12 - 4y )(3)

x = 36 - 12y

-12y = 36+x

y = (36+x)/(-12)

y = -(36+x)/12 or y = (-36-x)/12

AND WE ARE DONE <3

y=3-x/12

Step-by-step explanation:

x=4(3-y)(2^2-1)

x=4(3-y)(4-1)

x=3*4(3-y)

x=12(3-y)

x/12=3-y

y=3-x/12

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %