V=u+ 2at Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s?) and t is the
time (in seconds)
Find v when a is 4 m/s2, u is 3 m/s, and t is 72 seconds.

A.579 m/s
B.1728 m/s
C.436 m/s
D. 864 m/s

the answer is A 579m/s

Step-by-step explanation:

Given,

v=?    u=3m/s a=4m/s^2 and  t=72

Now,

v=u+2at

=3+2{4(72)}

= 3+2(288)

=3+576

=579m/s

answer: 20

step-by-step explanation: subtract the minimum date value from the maximum data value to find the date range. in this casem the date range is 42 - 22 = 20

hope this ! : ) ~zane

true? is that what you're asking or do you mean something else?