This math question is about logarithm​

(k+2h)/(k+h)

Step-by-step explanation:

log 6 12 = (log a 12)/(log a 6) ( Log base change property)

log a 12 = log a (3*4) = log a 3 + 2*log a 2 = k+2h

log a 6 = log a (2*3) = log a 3 + log a 2 = k+h

log 6 12 = (k+2h)/(k+h)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐