Find all solutions of the equation in the interval [0, 2 π). 2cos θ - √ 2 = 0
Write your answer in radians in terms of π. If there is more than one solution, separate them with commas.

θ =  

θ =

Step-by-step explanation:

2cosθ - √2 = 0

First, add √ 2 to both sides

2cosθ - √2 = 0

          +√2  +√2

2cosθ = √2

Divide both sides by 2

2cosθ/2 = √2 / 2

cosθ =

Use arccos to find θ

arccos() =  and   = θ

(3x-8) or (3x+8)

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116