A particle increases its speed from 8 x 105 m/s to 1.1 x 10 m/s. What
is the percentage increase?

Datos:

Vi=20m/s

Vf=30m/s

a=5m/s2

d=?

Cálculo de la distancia recorrida:

Vf^2 = Vi^2 + 2 * a * d

Reemplazando datos:

(30m/s)^2 = (20m/s)^2 + 2 * 5m/s2 * d

900m2/s2 = 400m2/s2 + 10m/s2 * d

900m2/s2 - 400m2/s2 = 10m/s2 * d

500m2/s2 = 10m/s2 * d

d = 500m2/s2 / 10m/s2

d = 50m

Step-by-step explanation:

the answer will be the last one