A bag contains 3 red, 5 blue, and 4 white marbles. If a marble is drawn from the bag, not replaced, and another is drawn, what is the probability of selecting a white and then blue marble?

you had all the marbles together which gives you 12,

then you add the White and the blue marbles together which gives you 9,

so u do 9/12

=3/4

5/33

Step-by-step explanation:

The probability of selecting a white marble is 4/12 = 1/3(because we have 4 white marbles and 12 marbles in total )

The probability of selecting a blue marble is 5/11 (because we have 5 blue marbles and 11 marbles left(1 has been drawn already) )

Probability of selecting a white and then blue marble equals 1/3*5/11 = 5/33

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

about 168 miles

step-by-step explanation: