Find the exact length of side a.​

Step-by-step explanation:

I think the best way to do this is to find B using the cos law. The two other angles are equal

b = 3sqrt(3)

a = 3

c = 3

b^2 = a^2 + b^2 - 2ab*cos(B)

(3sqrt(3)^2 = 3^2 + 3^2 - 2*3*3 * cos(B)

27 = 9 + 9 - 18*cos(B)

27 = 18 - 18*cos(B)

9 = - 18*cos(B)

9/-18 = cos(B)

-1/2 = cos(B)

B = cos-1(-1/2)

B = 120

<A + <C + 120 = 180

<A = <C

2A + 120 = 180

2A = 60

A = 30

The question says angle A so that's what I did.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)