In order to encourage pema to do her mathematics problems, her dad promise to pay Nu 5 for every problem She gets right, but he would take away Nu 3 for any moblem she missed. After working 20 problems, Pema was paid Nu 6o. How many problems did she solve correctly?​

The solution to he word problem leading to simultaneous equation is as follows;

The number of problems Pema is able to solve correctly is 15 problems

The method by which we arrived at the above value is as follows;

The given parameters of the question are;

Amount Pema's dad promise to pay her for every problem she gets right = Nu 5

Amount he would take away for any problem missed = Nu 3 (Therefore, Nu -3)

Amount Pema was paid after working 20 problems = Nu 60

Process;

Let x represent the number of problems she gets right (solves correctly), and let y represent the number of problems she missed, we have the following system of (simultaneous) equations;

x + y = 20...(1)

5·x - 3·y = 60...(2)

Multiplying equation (1) by 3 and adding the result to equation (2) gives;

3 × (x + y = 20) ⇒ 3·x + 3·y = 60

  5·x - 3·y = 60

+ 3·x + 3·y = 60

  8·x + 0 = 120

x = 120/8 = 15

x = 15

The number of problems she solves correctly, x = 15

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