Who can help me out with this one?​

(x + 1)² + (y - 2)² = 9

Step-by-step explanation:

Equation of the circle with center (h, k):

(x - h)² + (y -k)² = r²  where r is radius

Center(-1 , 2) ;  r =3

(x - [-1])² + (y - 2)² = 3²

(x + 1)² + (y - 2)² = 9

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.