the graph of the parabola y=3(x+5)2-2 has vertex (-5,-2). if this parabola is shifted 1 unit down and 6 units to the right, what is the equation of the new parabola?​

y = 3(x-1)^2 -3

Step-by-step explanation:

y = 3(x+5)^2 - 2

vertex: (-5, -2)

1 unit down :

-2 - 1 = -3

6 units to the right:

3(x+5-6)^2 -2

3(x-1)^2 - 2

make what's in the parenthesis equal to 0:

(x-1)^2 = 0

x = 1

or

-5 + 6 = 1

new vertex : (1, -3)

equation : y = 3(x-1)^2 -3

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse