Find x and y in the figure​

x=10, y=25

Step-by-step explanation:

First, in a trapezoid, the two angles on the same leg (the legs are the opposite sides that are not parallel) add up to 180 degrees. Therefore, 4y as well as (2y+3x) are supplementary. We can write this out as

4y + (2y+3x) = 180

6y+3x = 180

Next, the angles of a triangle add up to 180 degrees. Therefore, as the angles 2y, 4y, and (5x-20) make up a triangle, they add up to 180 degrees. We can write this as

4y + 2y + (5x-20) = 180

6y + 5x -20  =180

Our two equations are thus

6y + 5x - 20 = 180

6y + 3x = 180

If we subtract 6y from both sides in each equation, we can say

5x - 20 = 180-6y

3x = 180-6y

Therefore, we can write

5x-20 = 180-5y = 3x

5x-20=3x

subtract 3x from both sides to make all x variables on the same side

2x-20 = 0

add 20 to both sides to isolate the x and its coefficient

2x = 20

divide both sides by 2 to isolate x

x = 10

Therefore,

x = 10

6y + 3x = 180

6y + 30 = 180

subtract 30 from both sides to isolate the y and its coefficient

6y = 150

y = 25

answer: y=0 if that is what u r looking for