Another one i wanna dir :,) IF ray ST bisects ∠VSU, m∠VST = 6z+3, and m∠TSU = 3(z+12), calculate m∠VSU. Assume that point T is on the interior of ∠VSU.

∠VSU =   138°

Step-by-step explanation:

ST bisects ∠VSU

So, ∠VST = ∠TSU

6z + 3 = 3(z + 12)

6z + 3 = 3z + 3*12    {distributive property}

6z + 3 = 3z + 36       {Subtract 3 from both sides}

6z   = 3z +  36 - 3

6z = 3z + 33    {Subtract 3x from both sides}

6z - 3z = 33

3z = 33   {Divide both sides by 3}

z = 33/3

z = 11

∠VST = 6z + 3 = 6 *11 + 3

         = 66 + 3

         = 69

∠VSU = 69 + 69 = 138°

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!

2,160 π

step-by-step explanation: