Find the coefficient of the x4y2 term in the expansion of
(3x - y)
[ ? ]xy?

URGENT! Picture included

-540

Step-by-step explanation:

From binomial theorem, we can know

first term would be x^6

2nd term x^5

3rd term x^4

4th term x^3

Also, from binomial theorem, we can know

first term would be y^0

2nd term would be y^1

3rd term would be y^2

4th term would be y^3

We can see that we are looking for the 4th term (x^3y^3).

To find coefficient of 4th term, we use write:  

We can expand 6C3 using formula:    

Thus, the coefficient is -540

step-by-step explanation:

my butt

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w