What is the equation of the line that passes through the point (3,-7) and has a undefined slope

Answers:-

y = mx+b where m is the slope and b is the y intercept.

The line must pass through (3,-7) therefore

-7 =3 m +b

Now solve for b

b=-7 - 3m

Now substitute b into the definition of a line

y = mx -7 -3m

y=m*(x-3) -7

Now check the solution to see if for every m it passes through (3,-7)

substituting x in to the solution.

y=m(3–3)-7

y=7 hence the solution is correct. for any m

Plz follow ma );

y = 7

Step-by-step explanation:

y = mx+b where m is the slope and b is the y intercept.

The line must pass through (3,-7) therefore ---> -7 =3 m +b

Now solve for b ---> b=-7 - 3m

Now substitute b into the definition of a line, y = mx -7 -3m ---> y=m*(x-3) -7

Now check the solution to see if for every m it passes through (3,-7)

Substitute x in to the solution --->  y=m(3–3)-7

y=7 therefore the solution is correct.

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: