PLEASE HELP ASAP ! Quadrilateral OPQR is inscribed inside a circle as shown below. What is the measure of angle O? You must show all work and calculations to receive credit.

The measure of angle P is 43°

Step-by-step explanation:

If a quadrilateral is inscribed inside a circle, the sum of opposite angles are always equal to 180 degrees.

The angle POR is opposite to the angle PQR, and the angle OPQ is opposite to the angle ORQ.

So we have that:

mOPQ + mORQ = 180°

y + 3y + 8 = 180

4y = 172

y = 43°

So the measure of angle P is 43°.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet