A father is now twice as old as his son. If the sum of their ages ten years ago was fifty two, how old are they today?​

24 and 48

Today, the son is 24 years old, and the father is 48 years old.  

Step-by-step explanation:

(x - 10) + (2x - 10) = 52

3x + 20 = 52

3x = 72

x = 24

The father is 2 times his son's age.

2x

= 2(24)

= 48

So, the son is 24 and the father is 48.

10 years ago, son was 14 and father was 38, if added, this adds up to 52, so we know our calculations are correct.

So the son’s age is 24 and the father’s is 48. Ten years ago, they were 14 and 38, which adds up to 52.

Step-by-step explanation:

If the son’s age is x, the father’s age is 2x.

Ten years ago:

(x - 10) + (2x - 10) = 52

3x + 20 = 52

3x = 72

x = 24

2x = 48

line or a linear equation graph

step-by-step explanation:

-2

7 - 9 = -2

reversed:

-2 + 9 = 7