Quadrilateral ABCD has vertices A(–1, –2), B(–1, 3), C(4, 3) and D(4, –2). It’s dilated by a factor of 2 with the center of dilation at the origin. What are the coordinates of the resulting quadrilateral A’B’C’D

9514 1404 393

Step-by-step explanation:

Dilation about the origin multiplies each coordinate value by the dilation factor.

  A' = 2A = 2(-1, -2) = (-2, -4)

  B' = 2B = 2(-1, 3) = (-2, 6)

 C' = 2C = 2(4, 3) = (8, 6)

  D' = 2D = 2(4, -2) = (8, -4)

okay wait before i answer, is this for your points on a graph?

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47