90./04/ (C) 98.7877 TD) (D) 98.7777 12. If two perpendicular sides of a right-angled triangle are 5 cm and 12 cm, its perimeter is: (A) 13 cm (B) 17 cm (C) 27 cm (D) 30 cm 3. An article is purchased for 7,500 and sold for 8,400. The profit percent is : (A) 8% (B) 10%​

2) Option D is correct. If two perpendicular sides of a right-angled triangle are 5 cm and 12 cm, its perimeter will be 30cm.

3) None of the given options are correct. If an article is purchased for 7,500 and sold for 8,400, the profit percentage will be 12%

2) A right-angled triangle is a triangle with three sides and one of its angles is 90degrees. Find the image of a right-angled triangle attached below.

The triangle consists of 3 sides which are:

Before we can get the perimeter of the right triangle, we need to get the third side first (the hypotenuse side) using the Pythagoras theorem. According to the theorem:

Given

a = 5 cm

b =12 cm

Perimeter of the right triangle = a + b + c

Perimeter of the right triangle = 5 cm + 12 cm + 13 cm

Perimeter of the right triangle = 30 cm

Hence the perimeter of the right triangle is 30 cm.

3) If an article is purchased for 7,500, then;

If the same article is sold for 8,400, then:

Substitute the given parameters

This shows that the profit percent is 12%

Learn more on perimeter and percentage profit here:

1) D - 30 cm 2) 12 percents

Step-by-step explanation:

The first question was If two perpendicular sides of a right-angled triangle are 5 cm and 12 cm, its perimeter is: (A) 13 cm (B) 17 cm (C) 27 cm (D) 30 cm

two perpendicular sides are legs, find the hipotenuse of the triangle

It is equal to sqrt(5^2+12^2)= sqrt169=13

5+12+13=30 - D - the perimeter

The second question

7500 -100 percents

8400- x

7500/8400=100/x

75/84=100/x

(25/28)*x=100

(1/28)*x=4

x=4/(1/28)= 4*28= 112 percents

The profit is 12 percents

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180