Two lateral faces of a rectangular pyramid have a base length of 10 inches and a height of 15 inches. The other two lateral faces have a base length of 18 inches and a height of 13 inches. What is the surface area of the rectangular pyramid?

The surface area of the rectangular pyramid is the sum of the area of its individual surface. The surface area of the pyramid is 384 square inches.

Each surface of the rectangular pyramid has the shape of a triangle.

So that the area of each surface of the pyramid = x base x height.

From the given question;

The area of one of the two lateral faces = x b x h

                                                                 = x 10 x 15

The area of one of the two lateral faces = 75 square inches

Thus,

the area of the first two given lateral faces = 2 x 75

                                                            = 150 square inches

The area of the first two given lateral faces = 150 square inches

Also,

The area of one of the other two lateral faces = x b x h

                                                                             = x 18 x 13

The area of one of the other two lateral faces =  117 square inches

So that;

the area of the first two other lateral faces = 2 x 117

                                                            = 234 square inches

The area of the first two other lateral faces = 234 square inches

Thus,

the surface area of the pyramid = 150 + 234

                                                              = 384 square inches

Therefore, the surface area of the rectangular pyramid is 384 square inches.

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