pat has no more then 20 sweets. she counts her sweets by twos she has one sweet left. then she counts by five. she has 2 left over. how many sweets could she have​

She can either have 7 sweets or 17 sweets.

Step-by-step explanation:

Variable x = number of sweets Pat has

x < 20

Counting by 5's (5, 10, 15) that will result in 2 left over (5 + 2, 10 + 2, and 15 + 2). This leaves 3 possible options as to how many sweets Pat has: 7, 12, and 17.

Counting by 2's (2, 4, 6 . . . 18) that will result in 1 left over (6 + 1, 10 + 1, 16 + 1) This leaves 2 possible options, given the other numbers from counting by 5's were eliminated.: 7 and 17.

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

a

step-by-step explanation: