Given the triangle below, find the angle θ in radians. Round to four decimal places.

θ = 0.9626

Step-by-step explanation:

Hi there!

We're given the hypotenuse and the leg adjacent to θ in this right triangle. To find θ, we can use the cosine ratio:

Plug in the given information

Use the inverse cosine ratio

Plug this into your calculator (and ensure you're solving for radians instead of degrees in the settings)

Therefore, θ = 0.9626 when rounded to four decimal places.

I hope this helps!

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph