(x-3)/(-3) = 27 /3 - x

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

Write an equation in point-slope form for the line through the given point that has the given slope (-2,-7); m=-3/2

Find an equation for the linear function which has slope -10 and x-intercept -7