Write a polynomial in standard form with the zeros –4 0 1 and 4

Step-by-step explanation:

Hi there!

Zero of the polynomial is the value of "X" that gives final answer as zero.

So, as the polynomial in the second gives zero every time when we keep the zero which are given in the question. It is the answer.

Check:

• x⁴ - x³ - 16x² + 16x

Keep the value -4 as the value of X in polynomial.

= (-4)⁴-(-4)³ -16*(-4)²+16*(-4)

= 256+64-256-64

= 0

Keep the value 0 as the value of X in polynomial.

= (0)⁴-(0)³ -16*(0)²+16*(0)

= 0-0-0+0

= 0

Keep the value 1 as the value of X in polynomial.

= (1)⁴-(1)³ -16*(1)²+16*(1)

= 1-1-16+16

= 0

Keep the value 4 as the value of X in polynomial.

= (4)⁴-(4)³ -16*(4)²+16*(4)

= 256 - 64-256+64

= 0

Therefore, the correct answer is option B.

Hope it helps!

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: