Hannah went to the school store to buy supplies and spent $16. She bought four more pencils than pens and two fewer erasers than pens. Pens cost $1.25 each, pencils cost $0.55 each, and erasers cost $0.75 each. If x represents the number of pens Hannah bought, write an equation in terms of x that can be used to find how many of each item she bought. Use your equation to determine algebraically how many pens Hannah bought.

The algebaraic equation required is :

2.55x + 0.7 = 16

The number of pens Hannah bought is 6

If :

x = number of pens

4 more pencils Than pens ; Number of pencils = x + 4

2 fewer erasers than pens ; number of erasers = x - 2

Total amount spent = $16

The total number of items bought is :

(x) + (x + 4) + (x - 2)

Multiplying by the cost of each :

1.25x + 0.55(x+4) + 0.75(x-2)

Hence, Total amount spent can be represented as :

1.25x + 0.55(x+4) + 0.75(x-2) = 16

1.25x + 0.55x + 2.2 + 0.75x - 1.50 = 16

2.55x + 0.7 = 16

The algebraic equation is : 2.55x + 0.7 = 16

The number of pens Hannah bought can be calculated thus :

2.55x + 0.7 = 16

2.55x = 16 - 0.7

2.55x = 15.30

x = 15.30 / 2.55

x = 6

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solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.