Find three consecutive even integers so that twice the largest is 20 less than the sum of all three

If x is the smallest of the three, then the next two integers are x + 2 and x + 4.

"Twice the largest is 20 less than the sum of all three" translates to

2 (x + 4) = (x + (x + 4) + (x + 6)) - 20

Solve for x :

2x + 8 = 3x - 10

x = 18

Then the three numbers are {18, 20, 22}.

look below

Step-by-step explanation:Let x, x+2 & x+4 be the 3 integers.

x+2(x+2)=(x+4)+20

x+2x+4=x+4+20

3x+4=x+24

3x-x=24-4

2x=20

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1