Solve this by elimination method
a+2b=5
3a-b=1

(plz show the whole process)

a=1  b=2

Step-by-step explanation:

a+2b=5

3a-b=1

Multiply the second equation by 2

6a-2b=2

Add the two equations together

a+2b=5

6a-2b=2

7a    = 7

Divide by 7

7a/7 = 7/7

a=1

Now find b

3a-b =1

3(1) -b =1

3-b=1

Subtract 3 from each side

3-b-3=1-3

-b = -2

Multiply by -1

b=2

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11