8th grade math A box of chocolates contains 3 milk chocolates 2 dark chocolates, and 1 white chocolate You randomly select and eat three chocolates What is the probability that the first piece is milk chocolate, the second is dark chocolate, and the third is white chocolate

10 Milk chocolates

8 dark chocolates

6 white chocolates

24 TOTAL

\frac{10}{24} Probability that Hanissa choose a milk chocolate

Now, since she has already eaten one chocolate, then what's left is 23 chocolates.

So, since the second one should be a white chocolate and there are 6 of them, then

\frac{6}{23} - probability of choosing a white chocolate.

Then, multiply,

( \frac{10}{24} )( \frac{6}{23} )= \frac{60}{552} or \frac{5}{46}

5/46 or 10.87%

Step-by-step explanation:

there is 1/2 chance of your first being milk chocolate, 1/3 chance your second will be drake and 1/6 chance it will be white chocolate

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answer: 800

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