The sum of 5 consecutive integers is 110 what is the 4th number of this sequence

Step-by-step explanation:

Let 5 consecutive no. be

n, n+1,n+2,n+3,n+4

n+n+1+n+2+n+3+n+4=110

5n+10=110

5n=110-10

5n=100

n=100/5

n=20

4th term is n+3=20+3=23

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step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high

0.0076, if you meant 4.125 divided by 0.03125 it would be 132

step-by-step explanation:

first you have to move the decimal in 0.03125 over until its behind the 5 which is 5 places over. now the number is 3125

then you have to move the decimal in 4.125, 5 places over. now the number is 4,112,500.

now you divide like you would normally would and get 0.0076