A technician starts a job at a time Y1 that is uniformly distributed between 8:00 A. M. and 8:12 A. M. The amount of time to complete the job, Y2, is an independent random variable that is uniformly distributed between 20 and 30 minutes. What is the probability that the job will be completed before 8:30 A. M.

answer is c

step-by-step explanation:

81/12=324/x

x=48

change of stock price/initial stock price on friday * total stock value = change of stock value

0.89/73.73 *x = 42.72

x=3539.04 = total stock value at initial stock price on friday .

total stock value at initial stock price on friday/ initial stock price on friday = number of shares

3539.04/73.73 = 48 shares

they own 48 shares of this stock

3/8