2x-ky=14 and 5x-2y=5 In the system above, k is a constant and x and y are variables For what values of k will the system of equations have no solution.

Step-by-step explanation

In these type of questions we can use a trick to find answer

let's say we have two linear equation

1) ax+by+c=0

2)mx+ny+t=0

if  a/m = b/e ≠ c/f  that means we don't have any solution for these two equations ( that's because of analitic geometry)

so,

2x-ky-14=0

5x-2y-5=0

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

you can use a^2+ b^2=c^2