if the sum p(x)=ax^2-3x+b and q(x)=3x^3-12x^2+cx-13 is r(x)=3x^3-8x^2+3x-5,then find the value of a, b and c.

a=4, b=8, c=6

Step-by-step explanation:

ATQ, p(x) + q(x) = r(x)

3x^3-(12-a)x^2-(3-c)x+b-13 = 3x^3-8x^2+3x-5

Comparing the coefficients, we have

12-a=8, a=4

b-13=-5, b=8

-(3-c)=3, c=6

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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