A long spring is hung vertically with a weight attached to the bottom. Once the spring has stopped moving, the weight is pulled down exactly 0.766 meters and released. The time taken for the spring to perform exactly one "bounce" cycle is 5.92 seconds. What is the displacement from rest position, the velocity and the acceleration of the weight 103.47 seconds after being released?

2x+60=

step-by-step explanation:

f(x) is   are being squared

g(x) is   increasing by 2

h(x) is adding .25 each time

k(x) is taking the square root

f(x) and k(x) are exponential functions

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen