-X -y -32 = -9
Z= -3x - 1
z = 5y -Z + 23

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)

this "question" looks more like a project is there any other info you can give me about this. it could be too complex for someone else to do on this website