Please help me!! Find the equation of the line that is perpendicular to y=1/6x+3 and contains the point (-3,23).

Where ? = -6.

Step-by-step explanation:

We want to find the equation of a line that is perpendicular to:

And contains the point (-3, 23).

Recall that the slopes of perpendicular lines are negative reciprocals of each other.

The negative reciprocal of 1/6 is -6. Hence, the slope of the perpendicular line is -6.

We are also given that it passes through the point (-3, 23). Since we know the slope and a point, we can consider using the point-slope form:

Substitute:

Simplify:

Distribute:

And add. Hence:

In conclusion, our equation is:

Where ? = -6.