In the standard (x, y) coordinate plane, what is the distance, in coordinate units, between (8, 6) and (−2, −3) ?

√181 units

Step-by-step explanation:

P(x1,y1)=(8,6)

P(x2,y2)=(-2,-3)

steps are in the picture above.

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph