At what input value will the function f(x) = Vx – 5 + 2 begin to have real
outputs?
x = [?]

x=5 since if anything smaller than 0 it would be an imaginary number and would not be a real output

Step-by-step explanation:

5

Step-by-step explanation:

the function of f(x) = √(x – 5) + 2 will have real outputs , since √(x-5) ≥ 0

=> x - 5 ≥ 0

=> x ≥ 5

so, the input value begin from 5

for b its (t) and c its (d)

step-by-step explanation: