If AB= x+4, BC=2x-10, and AC=2x+1, then find the value for x

Step-by-step explanation:

Given:

We can illustrate this relationship as:

(2x + 1)

___↑___

| |

A — B — C

|____|___|

↓ ↓

(x + 4) (2x – 10)

_______________________________

When you are given an algebraic expression for the length of a segment, you can solve for that value by knowing that the sum of two segments AB + BC = AC.

Thus:

(x + 4) + (2x – 10) = (2x + 1)

[Regroup terms]

(x + 2x) + (4 – 10) = (2x + 1)

[Simplify]

(3x – 6) = (2x + 1)

[subtract 2x from both sides to isolate the variable]

(3x – 6) – 2x = (2x + 1) – 2x

[Regroup terms]

(3x – 2x) – 6 = (2x – 2x) + 1

x – 6 = 1

[Add 6 to both sides to isolate the constant]

x – 6 + 6 = 1 + 6

[Simplify]

x = 7

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841