Mathematics, 26.08.2021 14:00 lauryngrace37
The tangent of the curve f(t) =2+nt+mt^2 at point (1,1/2) is parallel to the normal g(t)= t^2+6t+13(-2,2), calculate the values m and n.
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Hi, can anyone show me how to do this problem? 100 points for this. in advance
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Find the value of x. give reasons to justify your solutions! h ∈ ig
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The tangent of the curve f(t) =2+nt+mt^2 at point (1,1/2) is parallel to the normal g(t)= t^2+6t+13(...
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