CẦN GẤP 1) -xy(x+3y-2)

3) (x-y)(x^2+xy+y^2)+(2x-y)(x-y)

2) 4xy(x-1/2xy+1)

4) 2x(x+y)-(4x+2y)(3x-y)

5) 4x(x+2)(y+3-x)

6) (4-xy)(5x-3y)-(x+y)(x-3y)

look a the sides they are perpendicular

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: