The mean useful life of car batteries is 55 months. They have a standard deviation of 2. Assume the useful life of batteries is normally distributed. a. Calculate the percent of batteries with a useful life of less than 51 months. (Round your answer to the nearest hundredth percent.) b. Calculate the percent of batteries that will last longer than 61 months. (Round your answer to the nearest hundredth percent.) a. Percent of batteries % b. Percent of batteries %

a. 0.13% b. 2.28%

Step-by-step explanation:

Let x denotes the useful life of batteries.

Given: months,

Since X is normally distributed.

The probability that batteries with a useful life of less than 38 months

The percent of batteries with a useful life of less than 38 months =0.13%

The probability that batteries will last longer than 68 months

The percent of batteries that will last longer than 68 months =2.28%

Step-by-step explanation:

part d

step-by-step explanation:

theresa talked her parents into getting sd cards for her phone and her brother’s phone. inserting an sd card into a phone gives it more storage. they both get 8-gigabyte sd cards. how many bits of storage come with each sd card? type your answer in both scientific and standard notation.

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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step-by-step explanation: