Three machines (A, B, C) are used to produce certain product. In one shift, they produce 130, 70 and 23 units respectively. Each machine produces a faulty unit with probability 1% for A, 5% for B and 13% for C. i. Find the proportion of faulty units produced. ii. Given a faulty unit, what is the probability that it was produced by B

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

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i think it’s a i believe