Simplify the radical
please explain process!​

Step-by-step explanation:

54 = 6*9

That means there are 3 threes and 1 two

54 = 2*3 * 3 * 3

There are a pair of 3s and a two and a 3 left over.

The two and the three remain under the root sigh.

One of the pair of threes comes out of the root sign.

The other one is thrown away.

sqrt(54) = 3*sqrt(6)

-2*3 sqrt6)

- 6 sqrt(6)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."