Mathematics, 30.08.2021 17:00 rileyeddins1010
suppose the velocity of a particle traveling along the x-axis is given by v(t)= 3t^2+8t+15 m/s at time t seconds. The particle is initially located 5 meters left of the origin. How far does the particle travel from t=2 seconds to t=3 seconds? After 3 seconds, where is the particle with respect to the origin?
Answers: 1
![\int\limits^3_2 {(3t^2+8t+15)} \, dt =\Bigg [ t^3+4t^2+15t\Bigg]^3_2\\\\=27+36+45-(8+16+30)\\\\=108-54\\\\=54 (m)\\\\](/tpl/images/2449/6388/43384.png)
![\int\limits^3_0 {(3t^2+8t+15)} \, dt =\Bigg [ t^3+4t^2+15t\Bigg]^3_2=108\\\\](/tpl/images/2449/6388/6af9f.png)
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